Let f(x+y)=f(x)f(y) for all x, y epsilon...

Let `f(x+y)=f(x)f(y)` for all `x, y epsilon R` and `f(x)=1+x phi (x) l n 2` where `lim_(xto0)phi(x)=1` then `f,(x)` is

A

`(a+b)f(x)`

B

`af(x)`

C

`bf(x)`

D

`-f(x)`

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The correct Answer is:

B

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