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The least value of the function `f(x)=x^3-18 x^2+96 x` in the interval `[0,9]` is 126 (b) 135 (c) 160 (d) 0

A

126

B

0

C

135

D

160

Text Solution

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The correct Answer is:
B
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VMC MODULES ENGLISH-DIFFERENTIAL CALCULUS 2-JEE Advanced (Archive)
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