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The function f(x)=(x^2-4)^n(x^2-x+1),n i...

The function `f(x)=(x^2-4)^n(x^2-x+1),n in N ,` assumes a local minimum value at `x=2.` Then find the possible values of `n`

A

‘n’ can be any odd number

B

‘n’ can only be an odd prime number

C

‘n’ can be any even number

D

‘n’ can only be a multiple of four

Text Solution

Verified by Experts

The correct Answer is:
C
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