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A function y=f(x) has a second-order der...

A function `y=f(x)` has a second-order derivative `f''(x)=6(x-1)dot` It its graph passes through the point (2,1) and at that point tangent to the graph is `y=3x-5,` then the value of `f(0)` is 1 (b) `-1` (c) 2 (d) 0

A

`(x-1)^(2)`

B

`(x-1)^(3)`

C

`(x+1)^(3)`

D

`(x+1)^(2)`

Text Solution

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The correct Answer is:
B
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