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If f and g are diferentiable functions in [0,1] satisfying `f(0) =2=g(1),g(0)and f(1)=6, ` then for some `c in (0,1)`

A

`2f'(c)=g'(c)`

B

2f'(c)=3g(c)

C

f(c)=g(c)

D

f'(c)=2g(c)

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The correct Answer is:
D
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