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If u=sqrt(a^2 cos^2 theta + b^2sin^2thet...

If `u=sqrt(a^2 cos^2 theta + b^2sin^2theta)+sqrt(a^2 sin^2 theta + b^2 cos^2 theta),` then the difference between the maximum and minimum values of `u^2` is given by : (a) `(a-b)^2` (b) `2sqrt(a^2+b^2)` (c) `(a+b)^2` (d) `2(a^2+b^2)`

A

`2(a^(2)+b^(2))`

B

`2sqrt(a^(2)+b^(2))`

C

`(a+b)^(2)`

D

`(a-b)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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