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If veca is perpendicular to vecb and vec...

If `veca` is perpendicular to `vecb` and `vecr` is a non-zero vector such that `pvecr + (vecr.vecb)veca=vecc`, then `vecr` is:

A

`vecc/p-((vecb.vecc)veca)/p^(2)`

B

`veca/p-((vecc.veca)vecb)/p^(2)`

C

`vecb/p-((veca.vecb)vecc)/p^(2)`

D

`vecc/p-((vecb.vecc)veca)/p^(2)`

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The correct Answer is:
To solve the problem, we need to find the vector \(\vec{r}\) given the conditions that \(\vec{a}\) is perpendicular to \(\vec{b}\) and the equation \(p\vec{r} + (\vec{r} \cdot \vec{b})\vec{a} = \vec{c}\). ### Step-by-Step Solution: 1. **Understand the given conditions**: - Since \(\vec{a}\) is perpendicular to \(\vec{b}\), we have: \[ \vec{a} \cdot \vec{b} = 0 \] 2. **Write the given equation**: - The equation provided is: \[ p\vec{r} + (\vec{r} \cdot \vec{b})\vec{a} = \vec{c} \] 3. **Rearranging the equation**: - We can rearrange the equation to isolate \(p\vec{r}\): \[ p\vec{r} = \vec{c} - (\vec{r} \cdot \vec{b})\vec{a} \] 4. **Express \(\vec{r}\)**: - Dividing both sides by \(p\) gives: \[ \vec{r} = \frac{\vec{c}}{p} - \frac{(\vec{r} \cdot \vec{b})\vec{a}}{p} \] 5. **Finding \(\vec{r} \cdot \vec{b}\)**: - To find \(\vec{r} \cdot \vec{b}\), we take the dot product of both sides of the rearranged equation with \(\vec{b}\): \[ \vec{b} \cdot (p\vec{r}) = \vec{b} \cdot \vec{c} - \vec{b} \cdot ((\vec{r} \cdot \vec{b})\vec{a}) \] - This simplifies to: \[ p(\vec{r} \cdot \vec{b}) = \vec{b} \cdot \vec{c} - (\vec{r} \cdot \vec{b})(\vec{b} \cdot \vec{a}) \] - Since \(\vec{a} \cdot \vec{b} = 0\), the second term vanishes: \[ p(\vec{r} \cdot \vec{b}) = \vec{b} \cdot \vec{c} \] 6. **Solving for \(\vec{r} \cdot \vec{b}\)**: - Thus, we have: \[ \vec{r} \cdot \vec{b} = \frac{\vec{b} \cdot \vec{c}}{p} \] 7. **Substituting back into the expression for \(\vec{r}\)**: - Now substitute \(\vec{r} \cdot \vec{b}\) back into the expression for \(\vec{r}\): \[ \vec{r} = \frac{\vec{c}}{p} - \frac{\left(\frac{\vec{b} \cdot \vec{c}}{p}\right)\vec{a}}{p} \] - This simplifies to: \[ \vec{r} = \frac{\vec{c}}{p} - \frac{\vec{b} \cdot \vec{c}}{p^2}\vec{a} \] 8. **Final expression for \(\vec{r}\)**: - Therefore, the final expression for \(\vec{r}\) is: \[ \vec{r} = \frac{\vec{c}}{p} - \frac{\vec{b} \cdot \vec{c}}{p^2}\vec{a} \]
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Statement 1: Let vecr be any vector in space. Then, vecr=(vecr.hati)hati+(vecr.hatj)hatj+(vecr.hatk)hatk Statement 2: If veca, vecb, vecc are three non-coplanar vectors and vecr is any vector in space then vecr={([(vecr, vecb, vecc)])/([(veca, vecb, vecc)])}veca+{([(vecr, vecc, veca)])/([(veca, vecb, vecc)])}vecb+{([(vecr, veca, vecb)])/([(veca, vecb, vecc)])}vecc

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