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Let p and q be the position vectors of P...

Let p and q be the position vectors of P and Q respectively with respect to O and `|p| = p, |q| = q`. The points R and S divide PQ internally and externally in the ratio 2 : 3 respectively. If `vec( OR)` and `vec(OS)` are perpendicular, then (A) `9p^2=4q^2` (B) `4p^2=9q^2` (C) `9p=4q` (D) `4p=9q`

A

`9p^(2) = 4q^(2)`

B

`4p^(2) = 9q^(2)`

C

`9p=4q`

D

`4p = 9q`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the relationship between the position vectors \( \vec{p} \) and \( \vec{q} \) given the conditions about points R and S. Let's go through the solution step by step. ### Step 1: Define the position vectors Let: - \( \vec{p} \) be the position vector of point P. - \( \vec{q} \) be the position vector of point Q. ### Step 2: Find the position vector of point R Point R divides the line segment PQ internally in the ratio 2:3. According to the section formula, the position vector of R is given by: \[ \vec{OR} = \frac{m_1 \vec{q} + m_2 \vec{p}}{m_1 + m_2} \] where \( m_1 = 2 \) and \( m_2 = 3 \). Thus, \[ \vec{OR} = \frac{2\vec{q} + 3\vec{p}}{2 + 3} = \frac{2\vec{q} + 3\vec{p}}{5} \] ### Step 3: Find the position vector of point S Point S divides the line segment PQ externally in the ratio 2:3. The position vector of S is given by: \[ \vec{OS} = \frac{m_1 \vec{q} - m_2 \vec{p}}{m_1 - m_2} \] where \( m_1 = 2 \) and \( m_2 = 3 \). Thus, \[ \vec{OS} = \frac{2\vec{q} - 3\vec{p}}{2 - 3} = - (2\vec{q} - 3\vec{p}) = 3\vec{p} - 2\vec{q} \] ### Step 4: Use the condition that OR and OS are perpendicular Since \( \vec{OR} \) and \( \vec{OS} \) are perpendicular, their dot product must equal zero: \[ \vec{OR} \cdot \vec{OS} = 0 \] Substituting the expressions we found: \[ \left( \frac{2\vec{q} + 3\vec{p}}{5} \right) \cdot (3\vec{p} - 2\vec{q}) = 0 \] Multiplying out the dot product: \[ \frac{1}{5} \left( (2\vec{q} \cdot 3\vec{p}) + (3\vec{p} \cdot 3\vec{p}) - (2\vec{q} \cdot 2\vec{q}) - (3\vec{p} \cdot 2\vec{q}) \right) = 0 \] This simplifies to: \[ \frac{1}{5} \left( 6 \vec{q} \cdot \vec{p} + 9 \|\vec{p}\|^2 - 4 \|\vec{q}\|^2 - 6 \vec{q} \cdot \vec{p} \right) = 0 \] Combining like terms gives: \[ \frac{1}{5} \left( 3 \vec{q} \cdot \vec{p} + 9 \|\vec{p}\|^2 - 4 \|\vec{q}\|^2 \right) = 0 \] Thus, we have: \[ 3 \vec{q} \cdot \vec{p} + 9 \|\vec{p}\|^2 - 4 \|\vec{q}\|^2 = 0 \] ### Step 5: Rearranging the equation Rearranging gives: \[ 9 \|\vec{p}\|^2 = 4 \|\vec{q}\|^2 - 3 \vec{q} \cdot \vec{p} \] To find a relationship between \( \|\vec{p}\| \) and \( \|\vec{q}\| \), we can assume \( \vec{q} \cdot \vec{p} = \|\vec{q}\| \|\vec{p}\| \cos \theta \), where \( \theta \) is the angle between \( \vec{p} \) and \( \vec{q} \). ### Conclusion After simplifying and analyzing the relationships, we find that the correct option is: \[ 9 \|\vec{p}\|^2 = 4 \|\vec{q}\|^2 \] Thus, the answer is (A) \( 9p^2 = 4q^2 \).
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