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The OABC is a tetrahedron such that OA^2...

The OABC is a tetrahedron such that `OA^2+BC^2=OB^2+CA^2=OC^2+AB^2`,then

A

OA is perpendicular to BC

B

OB is perpendicular to CA

C

OC is perpendicular to AB

D

AB is perpendicular to BC

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The correct Answer is:
A, B, C
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VMC MODULES ENGLISH-THREE DIMENSIONAL GEOMETRY -LEVEL-2
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