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Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/...

Let the line `(x-2)/(3)=(y-1)/(-5)=(z+2)/(2)` lies in the plane `x+3y-alphaz+beta=0`. Then, `(alpha, beta)` equals

A

`(6,-17)`

B

`(-6,7)`

C

`(5,-15)`

D

`(-5,15)`

Text Solution

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The correct Answer is:
B
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