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The two lines x=ay+b,z=cy+d and x=a'y+b'...

The two lines `x=ay+b,z=cy+d and x=a'y+b', z=c'y +d'` are pendicular to each other if

A

`a a' + c c'=1`

B

`(a)/(c') + (c )/(c')=1`

C

`(a)/(a')+ (c )/(c') =1`

D

`a a' + c c' =-1`

Text Solution

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The correct Answer is:
D
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