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A vessel contains 1.6g of dioxygen at ST...

A vessel contains 1.6g of dioxygen at STP(273.15k,1atm pressure). The gas is now trasnferred to another vessel at constnat temperature. Whre pressure becomes half of the original pressure. Calculate
( a) Volume of the new vessel.
(b) number of molecuels of dioxygen.

Text Solution

Verified by Experts

`p_(1) = 1` atm, `T_(1) = 273 K, V_(1) = ?`
32 g of oxygen occupies 22.4 L of volume at STP*
Hence, 1.6 g of oxygen will occupy, 16g oxygen `xx (22.4 L)/("32 g of oxygen") = 1.12 L`
`V_(1) = 1.12 L , p_(2) = (p_(1))/(2) = (1)/(2) = 0.5` atm `V_(2) = ?`
According to Boyle’s law: `p_(1)V_(1) = p_(2) V_(2) , V_(2) = (p_(1) xx V_(1))/(p_(2)) = (1 atm xx 1.12 L)/(0.5 atm) = 2.24 L`
(B) Number of molecules of oxygen in the vessel `= (6.022 xx 10^(23) xx 1.6)/(32) = 3.011 xx 10^(22)`
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