Home
Class 12
CHEMISTRY
A compound on analysis, gave the followi...

A compound on analysis, gave the following percentage composition :
Na=14.31%, S=9.97%, H=6.22%, O=69.5%
What would be the molecular formula of the compound assuming that all the hydrogen in the compound is reset in combination with oxygen as water of crystallisation. Molecular weight of the compound is 322.

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise Level - 1|75 Videos
  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise Level - 2|65 Videos
  • STOICHIOMETRY - I

    VMC MODULES ENGLISH|Exercise Level - 0 (Short Answer Type -II)|6 Videos
  • STATES OF MATTER

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-I|10 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|43 Videos

Similar Questions

Explore conceptually related problems

A compound on analysis gave the following percentage composition : Na= 14.31%, S = 9.97%, H = 6.22%, O = 69.50%. Calculate the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322. (At. wt. of Na = 23, S = 32, H = 1, O = 16)

A compound on analysis was found to contain the following composition : Na=14.31%,S=9.97%,O=69.50 %and H=6.22 % Calculate the molecular formula of the compound assuming that the whole of hydrogen in the compound is present as water of crystallisation. Molecular mass of the compound is 322.

A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55 Its VD is 44. Find the molecular formula of the compound.

A compound on analysis gave the follwing result C=54.54%, H=9.09% and vapour density of compound = 88.Determine the molecular formula of the compound.

An inorganic compound on analysis was found to have following composition : Mg = 9.76%, S = 13.01%, O = 26.01%, H_2O = 51.22% Calculate the empirical formula of the compound.

A substance on analysis, gave the following percentage composition : Na = 43.4 %, C = 11.3%, O = 45.3 %. Calculate the empirical formula. (Na = 23, C = 12, O = 16).

A substance on analysis, gave the following percentage composition : Na = 43.4 %, C = 11.3%, O = 45.3 %. Calculate the empirical formula. (Na = 23, C = 12, O = 16).

A compound was found of contain 14.34% oxygen. The minimum molecular weight of the compound is

A chemical compound is found to have the following composition : C = 19.5%, Fe = 15.2%, N = 22.8%, K = 42.5% Calculate the empirical formula of the compound. What will be the molecular formula if the molecular mass of the compound is 368 ?

1% solution of other compound is isotonic with 5% sucrose (sugar) solution. Then molecular wt. of compound will be :