How many atoms are present in one mole of `H_(2)SO_(4)` ?

Options

A. `7 xx 6.02 xx 10^(23)`
B. `1.5 xx 6.02 xx 10^(23)`
C. `6.02 xx 10^(23)`
D. `2 xx 6.02 xx 10^(23)`

Explanation

To determine how many atoms are present in one mole of \( H_2SO_4 \), we can follow these steps:

### Step 1: Identify the number of atoms in one molecule of \( H_2SO_4 \)
- The molecular formula \( H_2SO_4 \) indicates that there are:
- 2 Hydrogen (H) atoms
- 1 Sulfur (S) atom
- 4 Oxygen (O) atoms
- Therefore, the total number of atoms in one molecule of \( H_2SO_4 \) is:
\[ 2 \, (\text{H}) + 1 \, (\text{S}) + 4 \, (\text{O}) = 7 \, \text{atoms} \]

### Step 2: Calculate the number of atoms in one mole of \( H_2SO_4 \)
- One mole of any substance contains \( 6.02 \times 10^{23} \) entities (Avogadro's number).
- Since one molecule of \( H_2SO_4 \) contains 7 atoms, one mole of \( H_2SO_4 \) will contain:
\[ 7 \, \text{atoms/molecule} \times 6.02 \times 10^{23} \, \text{molecules/mole} = 7 \times 6.02 \times 10^{23} \, \text{atoms} \]

### Final Answer
Thus, the total number of atoms in one mole of \( H_2SO_4 \) is:
\[ 7 \times 6.02 \times 10^{23} \, \text{atoms} \]