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An element , X has the following isotopi...

An element , X has the following isotopic composition : `^(200)X : 90%,^(199)X:8.0%,^(202)X:2.0%` The weighted average atomic mass of the naturally occurring element X is closest to naturally occurring element X is closest to

A

200 u

B

210 u

C

202 u

D

199 u

Text Solution

Verified by Experts

The correct Answer is:
A
Average atomic mass `= ((90)/(100) xx 200) + ((8)/(100) xx 199) + ((2)/(100) xx 202) ~~ 200`
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