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Density of water is 1.00 g//cm^(3) and d...

Density of water is `1.00 g//cm^(3)` and density of ethanol is `0.9 g//cm^(3)`. If these two liquids were mixed to prepare a dilute solution then

A

density of the solution `gt 1.00 g//cm^(3)`

B

density of the solution `lt 1.00 g//cm^(3)`

C

density of the solution `lt 0.9 g//cm^(3)`

D

density of the solution `= 1 g//cm^(3)`

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The correct Answer is:
To solve the problem of finding the density of a mixture of water and ethanol, we will follow these steps: ### Step 1: Understand the Densities We know the densities of the two liquids: - Density of water (ρ_water) = 1.00 g/cm³ - Density of ethanol (ρ_ethanol) = 0.90 g/cm³ ### Step 2: Define the Volumes Assume we take: - A mL of water - B mL of ethanol ### Step 3: Calculate Masses Using the formula for mass (mass = density × volume): - Mass of water (m_water) = ρ_water × A = 1.00 g/cm³ × A mL = A grams - Mass of ethanol (m_ethanol) = ρ_ethanol × B = 0.90 g/cm³ × B mL = 0.90B grams ### Step 4: Calculate Total Mass Total mass (m_total) of the solution is the sum of the masses of water and ethanol: \[ m_{total} = m_{water} + m_{ethanol} = A + 0.90B \] ### Step 5: Calculate Total Volume Total volume (V_total) of the solution is the sum of the volumes of water and ethanol: \[ V_{total} = A + B \] ### Step 6: Calculate Density of the Mixture Density of the mixture (ρ_mixture) is given by the formula: \[ ρ_{mixture} = \frac{m_{total}}{V_{total}} = \frac{A + 0.90B}{A + B} \] ### Step 7: Analyze the Result To analyze the density further, we can express it in terms of A and B: - The numerator is \( A + 0.90B \) - The denominator is \( A + B \) ### Step 8: Determine the Range of Density Since: - \( A \) is a positive quantity (volume of water) - \( B \) is a positive quantity (volume of ethanol) We can conclude: 1. If \( B = 0 \) (only water), then \( ρ_{mixture} = 1.00 \) g/cm³. 2. If \( A = 0 \) (only ethanol), then \( ρ_{mixture} = 0.90 \) g/cm³. Thus, the density of the mixture will be between 0.90 g/cm³ and 1.00 g/cm³. ### Conclusion Therefore, the density of the solution when water and ethanol are mixed will be: \[ 0.90 \, \text{g/cm}^3 < ρ_{mixture} < 1.00 \, \text{g/cm}^3 \] ### Final Answer The density of the solution is less than 1 g/cm³ and greater than 0.90 g/cm³. ---

To solve the problem of finding the density of a mixture of water and ethanol, we will follow these steps: ### Step 1: Understand the Densities We know the densities of the two liquids: - Density of water (ρ_water) = 1.00 g/cm³ - Density of ethanol (ρ_ethanol) = 0.90 g/cm³ ### Step 2: Define the Volumes ...
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