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5 mL of N-HCl, 20 mL of N//2 H(2)SO(4) a...

`5 mL` of `N-HCl`, `20 mL` of `N//2 H_(2)SO_(4)` and `30 mL` of `N//3` `HNO_(3)` are mixed together and the volume is made to `1 L`. The normality of the resulting solution is

A

N/5

B

N/10

C

N/20

D

N/40

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(1)V_(1) + N_(2)V_(2) + N_(3)V_(3) = N_(4)V_(4), (V_(4) = V_(1) + V_(2) + V_(3) + V_(4))` or
`V_(4)` = Final volume = 1L `-= 1000 mL " "5 xx N + 20 xx (N)/(2) + 30 xx (N)/(3) = N_(4) xx 1000 " " :. N_(4) = (N)/(40)`
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