If `100 mL` of `H_(2) SO_(4)` and `100 mL` of `H_(2)O` are mixed, the mass percent of `H_(2) SO_(4)` in the resulting solution `(d_(H_(2)SO_(4)) = 0.9 g mL^(-1), d_(H_(2)O) = 1.0 gmL^(-1))`

Options

A. 90
B. 47.36
C. 50
D. 60

Answer

B

Explanation

Mass % of `H_(2)SO_(4) = ((0.9 xx 100))/((0.9 xx 100) + (1 xx 100)) xx 100% = (90)/(90 + 100) xx 100% = (90)/(190) xx 100% = 47.36%`