In the reaction:
`2Al(s)+6HCl(aq) to 2Al^(3+)(aq) +6Cl^(-)(aq)+3H_(2)(g)`

Options

A. 11.2 L `H_(2(g))` at STP is produced for every 3 L `H_(2(g))` produced
B. 6 L `HCl_((aq))` is consumed for every 3 L `H_(2(g))` produced
C. 33.6 L `H_(2(g))` is produced regardless of temperature and pressure for every mole Al that reacts
D. 67.2 L `H_(2(g))` at STP is produced for very mole Al that reacts.

Answer

A

Explanation

`Al_((s)) + 6HCl_((aq)) rarr 2Al_((aq))^(3+) + 6Cl_((aq))^(-) + 3H_(2(g))`
6 moles of HCl produced `H_(2)` at STP `= 3 xx 22.4 L`
`:.` 1 mole of HCl will produce `H_(2)` at STP `= (3 xx 22.4)/(6) = 11.2 L`