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An organic compound contains, C, H and S...

An organic compound contains, `C, H` and `S`. The minimum molecular weight of the compound containing `8%` sulphur is :
`("atomic weight of" S=32 "amu")`

A

`200 g mol^(-1)`

B

`400 g mol^(-1)`

C

`600 g mol^(-1)`

D

`300 g mol^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the minimum molecular weight of an organic compound containing 8% sulfur, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The compound contains Carbon (C), Hydrogen (H), and Sulfur (S). - The percentage of Sulfur in the compound is 8%. - The atomic weight of Sulfur (S) is given as 32 amu (or 32 g/mol). 2. **Assume the Total Mass of the Compound**: - For simplicity, we can assume we have 100 grams of the compound. This makes calculations easier since percentages can be directly converted to grams. - Therefore, in 100 grams of the compound, the mass of Sulfur (S) will be 8 grams (8% of 100 grams). 3. **Determine the Minimum Number of Sulfur Atoms**: - Since we are looking for the minimum molecular weight, we assume there is only one atom of Sulfur in the compound. This is because having more than one atom would increase the molecular weight unnecessarily for our minimum calculation. 4. **Calculate the Contribution of Sulfur to the Molecular Weight**: - The mass of one atom of Sulfur is 32 grams (as given). - Since we have 8 grams of Sulfur in our assumed 100 grams of compound, we can set up a proportion to find the total molecular weight of the compound: \[ \text{If } 8 \text{ g of S corresponds to } 32 \text{ g of S, then } 100 \text{ g of the compound corresponds to } x \text{ g of the compound.} \] - We can set up the equation: \[ \frac{8 \text{ g S}}{100 \text{ g compound}} = \frac{32 \text{ g S}}{x \text{ g compound}} \] 5. **Solve for x (the minimum molecular weight of the compound)**: - Cross-multiplying gives: \[ 8x = 3200 \] - Dividing both sides by 8: \[ x = \frac{3200}{8} = 400 \text{ g/mol} \] 6. **Conclusion**: - The minimum molecular weight of the compound containing 8% sulfur is **400 g/mol**. ### Final Answer: The minimum molecular weight of the compound is **400 g/mol**.

To find the minimum molecular weight of an organic compound containing 8% sulfur, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The compound contains Carbon (C), Hydrogen (H), and Sulfur (S). - The percentage of Sulfur in the compound is 8%. - The atomic weight of Sulfur (S) is given as 32 amu (or 32 g/mol). ...
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