The total pressure exerted by the mixture of equal moles of two gases is `5xx10^(3)NM^(-2)` in a container of volume 2 litres at 273K. Calculate the number of moles of the gases mixed.

Answer

0.473

Explanation

Vapour Density of mixture `xx 2` = Average molar mass of mixture
Average Molar Mass `= 38.3 xx 2 = 76.6`
For 100 gm mixture let mass of `{{:(NO_(2),N_(2)O_(4)),("x gm", "(100 - x)g"),((x)/(46)+(10-x)/(92),=(100)/(76.6)):}`
`rArr 100 + x = 120.1 rArr x = 20.1 gm , " "n_(NO_(2)) = (20.1)/(46) = 0.437`