1 L of a mixture of CO and `CO_(2)`, when passed through red hot tube containing charcoal, the volume becomes 1.6 L. all volumes are measured under the same conditions of temperature and pressure. Find the composition of the mixture.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Reaction
When the mixture of carbon monoxide (CO) and carbon dioxide (CO₂) is passed through a red-hot tube containing charcoal, only carbon dioxide reacts with charcoal to form carbon monoxide. The reaction can be represented as:
\[ \text{CO}_2 + \text{C} \rightarrow 2 \text{CO} \]

### Step 2: Define Variables
Let’s assume the volume of carbon dioxide in the original 1 L mixture is \( X \) liters. Therefore, the volume of carbon monoxide in the mixture will be:
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