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Three grams of salt of molecular weight 30 is dissolved in `250 g` of water. The molality of the solution is….

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The correct Answer is:
0.4
3.0 g of salt of molecular weight 30g is present in 250 g solution
`[["250 g water will make"],["250 ml solution"],[d_(H_(2)O) = "1 gm/mol"]] rarr (3)/(30) = 0.1` mole solute is present in 0.25L solution.
Hence, molarity `= (0.1)/(0.25) = 0.4 M`
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