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If 0.5 mole of BaCl(2) mixed with 0.20 m...

If 0.5 mole of `BaCl_(2)` mixed with 0.20 mole of `Na_(3) PO_(4)` the maximum number of moles of `Ba_(3)(PO_4)_(2)` then can be formed is

A

`0.70`

B

`0.20`

C

`0.20`

D

`0.10`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(3 BaCl_(2),+,2Na_(3)PO_(4),rarr,Ba_(3)(PO_(4))_(2)+6NaCl),("0.50 mole",,"0.20 mole",,"0.10 mole"),(,,"(Limiting Reagent)",,):}`
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