Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:

Options

A. 1.78 M
B. 2.00 M
C. 2.05 M
D. 2.22 M

Answer

C

Explanation

12g of urea is present in `rarr 1120 g` of solution `:.` 1120 gm solution has `(120)/(60) = 2` mole urea
`(1120)/(1.15)m` solution has 2 moles of urea `:.` Molarity `= (2)/(1120) xx 1.15 xx 1000 = 2.05 M`