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The number of photons emitted per second...

The number of photons emitted per second by a 60 W source of monochromatic light of wavelength 663 nm is:
`(h=6.63xx10^(-34)Js )`

A

`4xx10^(-20)`

B

`1.5xx10^(20)`

C

`2xx10^(-20)`

D

`2xx10^(20)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of photons emitted per second by a 60 W source of monochromatic light with a wavelength of 663 nm, we can follow these steps: ### Step 1: Understand the relationship between power, energy, and time The power (P) of the light source is defined as the energy (E) emitted per unit time (t): \[ P = \frac{E}{t} \] This means that the energy emitted per second is equal to the power of the source. ### Step 2: Calculate the energy of a single photon The energy (E) of a single photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: - \( h \) is Planck's constant (\( 6.63 \times 10^{-34} \, \text{Js} \)), - \( c \) is the speed of light (\( 3 \times 10^8 \, \text{m/s} \)), - \( \lambda \) is the wavelength of the light in meters. First, convert the wavelength from nanometers to meters: \[ \lambda = 663 \, \text{nm} = 663 \times 10^{-9} \, \text{m} \] Now, substitute the values into the energy formula: \[ E = \frac{(6.63 \times 10^{-34} \, \text{Js})(3 \times 10^8 \, \text{m/s})}{663 \times 10^{-9} \, \text{m}} \] ### Step 3: Calculate the energy of a single photon Now we can calculate \( E \): \[ E = \frac{(6.63 \times 10^{-34})(3 \times 10^8)}{663 \times 10^{-9}} \] \[ E = \frac{1.989 \times 10^{-25}}{663 \times 10^{-9}} \] \[ E \approx 2.998 \times 10^{-19} \, \text{J} \] ### Step 4: Calculate the number of photons emitted per second Now, we can find the number of photons emitted per second (N) using the formula: \[ N = \frac{P}{E} \] Substituting the values: \[ N = \frac{60 \, \text{W}}{2.998 \times 10^{-19} \, \text{J}} \] ### Step 5: Calculate the number of photons \[ N \approx \frac{60}{2.998 \times 10^{-19}} \] \[ N \approx 2.00 \times 10^{20} \, \text{photons/s} \] ### Final Answer The number of photons emitted per second by the 60 W source of monochromatic light of wavelength 663 nm is approximately: \[ N \approx 2.00 \times 10^{20} \, \text{photons/s} \] ---

To find the number of photons emitted per second by a 60 W source of monochromatic light with a wavelength of 663 nm, we can follow these steps: ### Step 1: Understand the relationship between power, energy, and time The power (P) of the light source is defined as the energy (E) emitted per unit time (t): \[ P = \frac{E}{t} \] This means that the energy emitted per second is equal to the power of the source. ### Step 2: Calculate the energy of a single photon ...
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