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An isobar of ""(20)^(40)Ca is...

An isobar of `""_(20)^(40)Ca` is

A

1-`._(18)^(40)Ar`

B

2-`._(20)^(38)Ca`

C

3-`._(1)^(1)H^(+)`

D

4-`._(18)^(38)Ar`

Text Solution

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The correct Answer is:
To find an isobar of \( _{20}^{40}Ca \) (Calcium-40), we need to understand the definition of isobars. Isobars are atoms that have the same atomic mass (mass number) but different atomic numbers. ### Step-by-Step Solution: 1. **Identify the mass number of Calcium-40**: - The mass number (A) of Calcium-40 is 40. This means it has a total of 40 protons and neutrons combined. 2. **Determine the atomic number of Calcium**: - The atomic number (Z) of Calcium is 20, which indicates that it has 20 protons. 3. **Find an element with the same mass number (40) but a different atomic number**: - We need to look for elements that have a mass number of 40 but do not have an atomic number of 20. 4. **List possible candidates**: - The atomic number of Argon (Ar) is 18, and it has a mass number of 40 (specifically, Argon-40). - The atomic number of Scandium (Sc) is 21, and it also has a mass number of 40 (specifically, Scandium-40). - Other elements like Potassium (K) and Titanium (Ti) do not have a mass number of 40. 5. **Select the correct isobar**: - Since Argon-40 and Scandium-40 both have a mass number of 40 but different atomic numbers (18 for Argon and 21 for Scandium), they are isobars of Calcium-40. 6. **Conclude the answer**: - Therefore, one isobar of \( _{20}^{40}Ca \) is \( _{18}^{40}Ar \) (Argon-40). ### Final Answer: An isobar of \( _{20}^{40}Ca \) is \( _{18}^{40}Ar \) (Argon-40).

To find an isobar of \( _{20}^{40}Ca \) (Calcium-40), we need to understand the definition of isobars. Isobars are atoms that have the same atomic mass (mass number) but different atomic numbers. ### Step-by-Step Solution: 1. **Identify the mass number of Calcium-40**: - The mass number (A) of Calcium-40 is 40. This means it has a total of 40 protons and neutrons combined. 2. **Determine the atomic number of Calcium**: ...
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A 0.50g sample of rock was found to have 2.5 xx 10^(-6) mol of ._(19)^(40)K (t_(1//2)=1.3 xx 10^(9) "yr") and 7.5 xx 10^(-6) mol of ._(20)^(40)Ca . How old is the rock?

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

(a) Find the energy needed to remove a neutron from the nucleus of the calcium isotope ._(20)^(42)Ca . (b) Find the energy needed to remove a proton from this nucleus. (c ) Why are these energies different? Mass of ._(20)^(40)Ca =40.962278u , mass of proton =1.007825 u .

(a) Find the energy needed to remove a neutron from the nucleus of the calcium isotopes ._(20)^(42)Ca (b) Find the energy needed to remove a proton from this nucleus (c ) Why are these energies different ? Atomic masses of ._(20)^(41)Ca and ._(20)^(42)Ca are 40.962278 u and 41.958622 u respectively.

Ratio of nuclear radii of ""^(135)Cs "to" ""^(40)Ca is

Draw the atomic diagrams of the following elements showing the distribution of - protons, neutrons & the electrons in the various shells of the atoms. (a) Carbon ""_(6)^(12)C (b) Oxygen ""_(8)^(16)O (c) Phosphorus ""_(15)^(31)P (d) Argon ""_(18)^(40)Ar (e) Calcium ""_(20)^(40)Ca [The upper number represents the - mass number & the lower number the - atomic number e.g. calcium - mass number = 40, atomic number = 20]

A compound has a fortmula = ''H_(2)Y'' . Y denotes a non - metal. State the following: The formula of the compound formed between calcium [""_20^(40)Ca] and Y.

The ratio of density of nuciel of O^(16) and Ca^(40) is :

If m_(p) is the mass of proton. m_(n) that of a neutron, M_(1) that of _(10)Ne^(20) nucleus and M_(2) that of _(20)Ca^(40) nucleus, then which of the following relations is//are not true?

Let m_p be the mass of a proton , m_n the mass of a neutron, M_1 the mass of a ._10^20Ne nucleus and M_2 the mass of a ._20^40Ca nucleus . Then

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