Number of electrons that F (Z = 9) has in p-orbitals is equal to:

Options

A. number of electrons in s-orbitals in Na
B. number of electrons in d-orbitals in `Fe^(3+)`
C. number of electrons in d-orbitals in Mn
D. (A), (B) and (C) true

Explanation

To determine the number of electrons that fluorine (F) with atomic number Z = 9 has in its p-orbitals, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Number**:
- The atomic number of fluorine (F) is 9. This means it has 9 electrons.

2. **Write the Electronic Configuration**:
- The electronic configuration of an element describes how its electrons are distributed among the various atomic orbitals. For fluorine, the electronic configuration is:
\[ 1s^2 \, 2s^2 \, 2p^5 \]
- This means that there are 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, and 5 electrons in the 2p orbital.

3. **Count the Electrons in the p-Orbitals**:
- From the electronic configuration, we can see that the number of electrons in the p-orbitals (2p) is 5.

4. **Conclusion**:
- Therefore, the number of electrons that fluorine has in its p-orbitals is **5**.

### Final Answer:
The number of electrons that F (Z = 9) has in p-orbitals is **5**.

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