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The first emission line in the atomic sp...

The first emission line in the atomic spectrum of hydrogen in the Balmer series appears at`

A

`(9R_(H))/(400)cm^(-1)`

B

`(7R_(H))/(144)cm^(-1)`

C

`(3R_(H))/(4)cm^(-1)`

D

`(5R_(H))/(36)cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
First line in Balmer series is due `n=3 rarrn=2` transition.
`bar(v)=R_(H)((1)/(4)-(1)/(9))=R_(H).(5)/(36)`
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