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Energy of H-atom in the ground state is ...

Energy of H-atom in the ground state is -13.6 eV, hence energy in the second excited state is

A

1.51 eV

B

3.4 eV

C

6.04 eV

D

13.6 eV

Text Solution

Verified by Experts

The correct Answer is:
A
`2^("nd")` excited state will be the `3^("rd")` energy level.`" "E_(n)=(13.6)/(n^(2))eV or E = (13.6)/(9)=1.51eV`
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