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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV`. The possible energy values (s) of the excited state (s) for electron in bohr orbits of hydrogen is (are)

A

`-3.4eV`

B

`-4.2eV`

C

`-6.8eV`

D

`+6.8eV`

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The correct Answer is:
To find the possible energy values of the excited states for an electron in Bohr orbits of a hydrogen atom, we can follow these steps: ### Step 1: Understand the Energy Formula The energy of an electron in the nth Bohr orbit of a hydrogen atom is given by the formula: \[ E_n = -\frac{13.6 \, Z^2}{n^2} \, \text{eV} \] where \( Z \) is the atomic number (for hydrogen, \( Z = 1 \)) and \( n \) is the principal quantum number (n = 1, 2, 3, ...). ### Step 2: Calculate the Energy for the First Orbit For the first Bohr orbit (n = 1): \[ E_1 = -\frac{13.6 \times 1^2}{1^2} = -13.6 \, \text{eV} \] ### Step 3: Calculate the Energy for the Second Orbit For the second Bohr orbit (n = 2): \[ E_2 = -\frac{13.6 \times 1^2}{2^2} = -\frac{13.6}{4} = -3.4 \, \text{eV} \] ### Step 4: Calculate the Energy for Higher Orbits For the third Bohr orbit (n = 3): \[ E_3 = -\frac{13.6 \times 1^2}{3^2} = -\frac{13.6}{9} \approx -1.51 \, \text{eV} \] For the fourth Bohr orbit (n = 4): \[ E_4 = -\frac{13.6 \times 1^2}{4^2} = -\frac{13.6}{16} = -0.85 \, \text{eV} \] ### Step 5: Generalize for Higher Excited States The energy values for higher excited states (n = 5, 6, ...) will continue to be less negative (closer to zero) as n increases. Thus, the energies will be: - \( E_5 \approx -0.54 \, \text{eV} \) - \( E_6 \approx -0.38 \, \text{eV} \) - and so on... ### Conclusion The possible energy values of the excited states for the electron in the Bohr orbits of hydrogen are: - \( E_2 = -3.4 \, \text{eV} \) - \( E_3 \approx -1.51 \, \text{eV} \) - \( E_4 \approx -0.85 \, \text{eV} \) - Higher excited states will have energies that are less negative. ### Final Answer The possible energy values of the excited states for the electron in Bohr orbits of hydrogen include: - \( -3.4 \, \text{eV} \) (for n = 2) - \( -1.51 \, \text{eV} \) (for n = 3) - \( -0.85 \, \text{eV} \) (for n = 4) - and so on...

To find the possible energy values of the excited states for an electron in Bohr orbits of a hydrogen atom, we can follow these steps: ### Step 1: Understand the Energy Formula The energy of an electron in the nth Bohr orbit of a hydrogen atom is given by the formula: \[ E_n = -\frac{13.6 \, Z^2}{n^2} \, \text{eV} \] where \( Z \) is the atomic number (for hydrogen, \( Z = 1 \)) and \( n \) is the principal quantum number (n = 1, 2, 3, ...). ### Step 2: Calculate the Energy for the First Orbit ...
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