Each rubidium halide crystallising in the NaCl-type lattice has a unit cell length `0.30 Å` greater than that for corresponding potassium salt `(r_(k+)=1.33 Å`) of the same halogen. Hence, ionic radius of `Rb^(+)` is

Options

A. `1.18 Å`
B. `1.43 Å`
C. `1.63 Å`
D. `1.03 Å`

Explanation

To find the ionic radius of \( Rb^+ \), we can follow these steps:

### Step 1: Understand the relationship between edge length and ionic radius in the NaCl-type lattice
In a NaCl-type lattice, the relationship between the edge length \( a \) of the unit cell and the ionic radius \( r \) is given by the formula:
\[ a = 2\sqrt{2}r \]

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