A metal has bcc structure and the edge length of its unit cell is `3.04overset(@)(A)`. The volume of the unit cell in `cm^(3)` will be

Options

A. (a) `1.6xx10^(-21) cm^(3)`
B. (b) `2.81xx10^(-23) cm^(3)`
C. (c) `6.02xx10^(-23) cm^(3)`
D. (d) `6.6xx10^(-24)cm^(3)`

Explanation

To find the volume of a body-centered cubic (BCC) unit cell with an edge length of \(3.04 \, \text{Å}\), we can follow these steps:

### Step 1: Convert the edge length from angstroms to centimeters
1 angstrom (Å) = \(10^{-10}\) meters
1 meter = 100 centimeters
Thus, \(1 \, \text{Å} = 10^{-10} \, \text{m} = 10^{-10} \times 100 \, \text{cm} = 10^{-8} \, \text{cm}\)

Now, convert \(3.04 \, \text{Å}\) to centimeters:
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