A compound of formula `A_(2)B_(3)` has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms

Options

A. hcp lattice-B, `(2)/(3)` Tetrachedral voids-A
B. hcp lattice-A, `(2)/(3)` Tetrachedral voids-B
C. hcp lattice-A, `(1)/(3)` Tetrachedral voids-B
D. hcp lattice-B, `(1)/(3) underset(h rarr 0 )(lim)` Tetrachedral voids-A

Explanation

To solve the problem, we need to analyze the structure of the compound \( A_2B_3 \) and determine which atom forms the hcp lattice and the fraction of tetrahedral voids occupied by the other atom.

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound has the formula \( A_2B_3 \) and is stated to have a hexagonal close-packed (hcp) lattice. In an hcp structure, one type of atom typically occupies the lattice points, while the other type occupies the voids.

**Hint**: Remember that in hcp structures, one atom type usually forms the close-packed arrangement.
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