A force F is applied on a block kept at the smooth surface in contact with the wall. If the block is at rest, the forces applied by block on surface (1) is `F_(1)` and on surface (2) is `F_(2)`. Find `(F_(1))/(F_(2))` (Take g=10 `m//s^(2))`

Options

A. `2:1`
B. `1:2`
C. `1:1`
D. none of these

Answer

a

Explanation

`N_(1)`=Normal reaction applied by surface 1 on block =`f_(1)`
`N_(1)=100sqrt(2) cos 45^(@)+100=100+100`
`N_(1)=200 N`
fore applied by block = action / Reaction pari =200 N
`F_(2)=100 N=N_(2) , (F_(1))/(F_(2))=2.1`