A 10 kg steel ball is suspended by two strings as shown. The tensions in the two strings are: (g=9.8 `m//s^(2)`)

Options

A. 196 N and 98 N
B. `98sqrt(3` N and `98sqrt(2)`N
C. `(196)/(1+sqrt(3))` N and `(98sqrt(2))/(1+sqrt(3))` N
D. `(98)/sqrt(3)` N and `(196)/sqrt(6)` N

Answer

c

Explanation

`T_(2) cos 45 =TT_(1) cos 60`
`rarr T_(1)=T_(2)sqrt(2)`
`rarr(T_(2))/sqrt(2)+(T_(2)sqrt(2))sqrt(3)/(2)=10g rarr (T_(2)+T_(2)sqrt(3))/sqrt(2)=10g rarr T_(2)=(10sqrt(2)g)/(1+sqrt(3)),T_(1)=(20g)/(1+sqrt(3))`