A particle moving with speed v(0)=10sqr...

A particle moving with speed `v_(0)=10sqrt(2) ms^(-1)` strikes a wall at an angle `45^(@)` as shown in figure. Find magnitude of change in velocity.

`10sqrt(2) ms^(-1)`

zero

`20 ms^(-1)`

`10 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`trianglebarv=barv_(2)-barv_(1)=sqrt(2v_(0))=20 m/s`

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