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Let overset(rarr)C = overset(rarr)A+over...

Let `overset(rarr)C = overset(rarr)A+overset(rarr)B` then :

A

`|overset(rarr)C|` is always greater then `|overset(rarr)A|`

B

it is possible to have and `|overset(rarr)C| lt |overset(rarr)B|`

C

`|overset(rarr)C|` is always equal to `|overset(rarr)A + overset(rarr)B|`

D

`|overset(rarr)C|` is never equal to `|overset(rarr)A+overset(rarr)B|`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the vector equation given: \[ \overset{\rarr}{C} = \overset{\rarr}{A} + \overset{\rarr}{B} \] We will evaluate the options based on vector properties. ### Step 1: Understanding the vector addition The equation states that vector \( \overset{\rarr}{C} \) is the resultant of vectors \( \overset{\rarr}{A} \) and \( \overset{\rarr}{B} \). According to the triangle law of vector addition, the magnitude of the resultant vector \( C \) can be expressed in terms of the magnitudes of \( A \) and \( B \). ### Step 2: Applying the triangle inequality From the triangle inequality, we know that: \[ |\overset{\rarr}{A}| + |\overset{\rarr}{B}| > |\overset{\rarr}{C}| \] This implies that the sum of the magnitudes of vectors \( A \) and \( B \) is always greater than the magnitude of vector \( C \). ### Step 3: Analyzing the options 1. **Option A**: \( |\overset{\rarr}{C}| \) is always greater than \( |\overset{\rarr}{A}| \). - This is not necessarily true, as \( |\overset{\rarr}{C}| \) can be less than \( |\overset{\rarr}{A}| \) if \( \overset{\rarr}{B} \) is in the opposite direction of \( \overset{\rarr}{A} \). 2. **Option B**: \( |\overset{\rarr}{C}| \) can be less than \( |\overset{\rarr}{B}| \). - This is possible if \( \overset{\rarr}{A} \) is in the opposite direction to \( \overset{\rarr}{B} \) and has a greater magnitude. Thus, this option can be correct. 3. **Option C**: \( |\overset{\rarr}{C}| \) is always equal to \( |\overset{\rarr}{A}| + |\overset{\rarr}{B}| \). - This is incorrect because equality holds only when \( \overset{\rarr}{A} \) and \( \overset{\rarr}{B} \) are in the same direction. 4. **Option D**: \( |\overset{\rarr}{C}| \) is never equal to \( |\overset{\rarr}{A}| + |\overset{\rarr}{B}| \). - This is also incorrect because \( |\overset{\rarr}{C}| \) can equal \( |\overset{\rarr}{A}| + |\overset{\rarr}{B}| \) when both vectors are in the same direction. ### Conclusion The correct option is **Option B**: \( |\overset{\rarr}{C}| \) can be less than \( |\overset{\rarr}{B}| \).

To solve the problem, we need to analyze the vector equation given: \[ \overset{\rarr}{C} = \overset{\rarr}{A} + \overset{\rarr}{B} \] We will evaluate the options based on vector properties. ...
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Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=aB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means overset(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , overset(rarr)A=hat i+ hat j-hatk and overset(rarr)B=2 hat i +3 hat j +5 hat k angle between overset(rarr)A and overset(rarr)B is

If |overset(rarr)A-overset(rarr)B|=|overset(rarr)A|-|overset(rarr)B| the angle between overset(rarr)A and overset(rarr)B is

The maqunitudes of vecotr overset(rarrA), overset(rarr)B and overset(rarr)C are respectively 12,5 and 13 units and overset(rarr)A+overset(rarr)B=overset(rarr)C then the angle between overset(rarr)A and overset(rarr)B is :

At what angle the two force overset(rarr)A+overset(rarr)B and overset(rarr)A-overset(rarr)B act so that their resultant is sqrt(3A^(2)+B^(2)) ?

Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=AB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means ovsert(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , For non zero vectors overset(rarr)A, overset(rarr)B, overset(rarr)C,|(overset(rarr)Axxoverset(rarr)B).overset(rarr)C|=|overset(rarr)A||overset(rarr)B||overset(rarr)C| holds if and only if

Three vectors overset(rarr)P,overset(rarr)Q and overset(rarr)R are shown in the figure. Let S be any point on the vector overset(rarr)R The distance between the point P and S is |overset(rarr)R| . The general relation among vectors overset(rarr)P,overset(rarr)Q and overset(rarr)S is :

Dot product of two vectors overset(rarr)A and overset(rarr)B is defined as overset(rarr)A.overset(rarr)B=aB cos phi , where phi is angle between them when they are drawn with tails coinciding. For any two vectors . This means overset(rarr)A . overset(rarr)B=overset(rarr)B. overset(rarr)A that . The scalar product obeys the commutative law of multiplication, the order of the two vectors does not matter. The vector product of two vectors overset(rarr)A and overset(rarr)B also called the cross product, is denoted by overset(rarr)A xx overset(rarr)B . As the name suggests, the vector product is itself a vector. overset(rarr)C=overset(rarr)A xx overset(rarr)B then C=AB sin theta , A force overset(rarr)F=3hat i +c hat j + 2 hatk acting on a particle causes a displacement d=4hat i- 2 hat j + 3 hat k . If the work done (dot product of force and displacement) is 6J then the value of c is :

If |overset(rarr)A+overset(rarr)B|=|overset(rarr)A-overset(rarr)B| what is the angle between overset(rarr)A and overset(rarr)B ?

The angle between vector (overset(rarr)Axxoverset(rarr)B) and (overset(rarr)B xx overset(rarr)A) is :

The angle between vector (overset(rarr)Axxoverset(rarr)B) and (overset(rarr)B xx overset(rarr)A) is :

VMC MODULES ENGLISH-INTRODUCTION TO VECTORS & FORCES -level 2
  1. If overset(rarr)A+overset(rarr)B+overset(rarr)C =0 and A = B + C, th...

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  2. The maximum and minimum magnitude of the resultant of two given vector...

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  3. Let overset(rarr)C = overset(rarr)A+overset(rarr)B then :

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  4. The resultant of vecP and vecQ is perpendicular to vecP. What is the a...

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  5. If overset(rarr)B=noverset(rarr)A and overset(rarr)A is antiparall...

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  6. The x-component of the resultant of several vectors

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  7. Find the resultant of the three vectors vec(OA), vec(OB) and vec(OC) s...

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  8. If PR = RQ, then :

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  9. Given that vec(A)+vec(B)+vec(C )=0.Out of three vectors,the two equal ...

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  10. ABCDEF is regular hexagon with point O as centre. The value of overse...

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  11. The block shown is moving with constant velocity. Find mu(k) between...

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  12. Three forces of magnitudes 6 N, 6 N an d sqrt(72) N act at corner of c...

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  13. What minimum force F is required to move this 4 kg block if it acts at...

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  14. The minimum force F for which the block starts moving is Find x

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  15. A block of mass 1 kg is pushed against a rough vertical wall of mu=0...

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  16. A metal sphere is hung by a string fixed to a wall. The sphere is push...

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  17. Find mu(s) between A and B.

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  18. A uniform sphere of weight W and radius 5 cm is being held by string a...

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  19. A large hemi sphere of radius 100m is fixed on the ground. A man weigh...

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  20. A particle moves along x-axis such that its position veries with time ...

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