Two forces are applied on a system of blocks as shown. The block remains in equilibrium on the smooth surface. Then choose the correct option(s).

Options

A. (a)`F=F_(1) cos theta`
B. (b)The normal force between the two blocks is F
C. (c)The normal force between the two blocks is `f-f_(1) cos theta`
D. (d)The normal force exerted by the ground on the block of mass `m_(1)` is `m_(1)`g

Answer

ab

Explanation

For equilibrium of `m_(2)`
N=F
for equilibrium of `m_(1)`
`f_(1)cos theta =N`
? `F_(1) sin theta +m_(1)g =N_(1)`
form (i) and (ii) : F=`f_(1) cos theta`