In the figure shown, the strings and pulleys are massless. The blocks are in equilibrium. If the force by the clamp on the pulley is `sqrt(8/3)` mg then `(M)/(m)` is equal to

Answer

0.67

Explanation

Balancing forces of m T mg let the force on pulley by clamp be `f_(c ) rarr` for pulley to be in equilibrium `f_(c )` should be equal and opposite to resultant of T and 1

`rarr sqrt(8)/(3) mg = mg sqrt(2(1+cos theta)) rarr cos theta =1/3 =0.33`
`2T cos theta =Mg rarr 2m g1/3 =M g rarr (M)/(m) =2/3 =0.067`