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Three forces start acting simultaneously...

Three forces start acting simultaneously on a particle moving with velocity `vec(v)`. These forces are represented in magnitude and direction by the three sides os a triangle ABC (as shown). The particle will now move with velocity.

A

(a)`overset(rarr)v` remaining unchanged

B

(b)less than `overset(rarr)v`

C

(c)greater than `overset(rarr)v`

D

(d)`|overset(rarr)v|` in the direction of the largest force BC

Text Solution

Verified by Experts

The correct Answer is:
a
From polygon law of vector addition we know if the vectors are arranged along the sides of a polygon the resultant of vector becomes zero. Here in this case the forces are represented by the sides of a triangle taken in same order, so their resultant is zero. It means the acceleration of the particle should be zero, hence velocity remains constant.
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