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A particle is projected from origin in x...

A particle is projected from origin in xy-plane and its equation ,of trajectory is given by `y = ax - bx^(2)`. The only acceleration ,in the motion is' f' which is constant and in `-ve` direction of, y-axis then
Find the velocity of projection and the angle of projection.

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AI Generated Solution

To solve the problem step by step, we will analyze the given trajectory equation and derive the required quantities. ### Step 1: Understand the trajectory equation The trajectory of the particle is given by the equation: \[ y = ax - bx^2 \] This is a quadratic equation in \(x\) and represents a parabola opening downwards. ### Step 2: Compare with the standard trajectory equation ...
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