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The approximate value of g (in m//s^2) a...

The approximate value of g (in `m//s^2`) at an altitude above Earth equal to one Earth diameter is:

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Given `vecu=hati+2hatjm s^(-1)`
As `vecu=u_(x)u+u_(y)hatj therefore u_(x)=1ms^(-1) and u_(y)=2ms^(-1)`
Also, `x=u_(x)t therefore x=x=t and y=u_(y)t-1/2 gt^(2)`
`y=2t-1/2 xx 10 xx t^(2)=2t-5t^(2)`
Equation of trajectory is `y=2x-5x^(2)`
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