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If the horizontal range of projectile be...

If the horizontal range of projectile be (a) and the maximum height attained by it is (b) then prove that the velocity of projection is
` [ 2 g (b+ a^2 /(16 b)) ] ^(1//2)`.

Text Solution

AI Generated Solution

To prove that the velocity of projection \( u \) is given by the formula \[ u = \sqrt{2g \left( b + \frac{a^2}{16b} \right)} \] where \( a \) is the horizontal range and \( b \) is the maximum height attained by the projectile, we can follow these steps: ...
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