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In the masses of A and B are 10 kg and 5...

In the masses of A and B are 10 kg and 5 kg . Calculate the minimum mass of C which may stop A from slipping Coefficient of static friction between block A and table is 0.2
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Text Solution

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Here, `m_(A) = 10 kg, m_(B) = kg`, `m_(c) = ? Mu = 0.2`
To avoid slipping of A, Force of friction = T = wt. of B
`mu (m_(c) + m_(A)) g = M_(B) g` 0.2 (m + 10) s, `m + 10 = (5)/(0.2) = 25` m = 25 - 10 = 15 kg
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