In the figure, blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. `F_(1)` and `F_(2)` are external forces of magnitudes 2mg and mg respectively, then :

Options

A. `a_(1) = a_(2) = a_(3)`
B. `a_(1) gt a_(2) gt a_(3)`
C. `a_(1) = a_(2), a_(2) gt a_(3)`
D. `a_(1) gt a_(2), a_(2) = a_(3)`

Answer

B

Explanation

`a_(1) = (2mg - mg)/(m) g, a_(2) = (2mg - mg)/(3m) = (g)/(3)` and `a_(3) = (mg - mg)/(m) = 0` `:. a_(1) gt a_(2) gt a_(3)`