A system is at rest as shown in figure. The tension in the string in `T_(1)`. When the 2 kg block is removed, the system moves with some acceleration a and tension in string becomes `T_(2)` Find `T_(1)//T_(2)` .

Options

A. `(9)/(8)`
B. `(10)/(9)`
C. `(9)/(11)`
D. `(11)/(9)`

Answer

A

Explanation

When 2 kg block is removed, acceleration `= (10 g - 8g)/(18), = (2g)/(18) m//s^(2)`
`10 g - T_(2) = 10 ((2g)/(18))`, `T_(2) = (160)/(18)`, `= (T_(1))/(T_(2)) = (9)/(8)`