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An ice cube is kept on an inclined plane...

An ice cube is kept on an inclined plane of angle `30^(@)`. The coefficient to kinetic friction between the block and incline plane is the `1//sqrt(3)`. What is the acceleration of the block ?

A

zero

B

`2 ms^(-2)`

C

`1.5 ms^(-2)`

D

`5 ms^(-2)`

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The correct Answer is:
To find the acceleration of the ice cube on the inclined plane, we can follow these steps: ### Step 1: Identify the Forces Acting on the Ice Cube The forces acting on the ice cube are: 1. The gravitational force (weight) acting downwards: \( F_g = mg \) 2. The normal force \( N \) acting perpendicular to the inclined plane. 3. The frictional force \( F_f \) acting up the incline. ### Step 2: Resolve the Gravitational Force The weight of the ice cube can be resolved into two components: - Perpendicular to the incline: \( F_{g\perp} = mg \cos \theta \) - Parallel to the incline: \( F_{g\parallel} = mg \sin \theta \) For \( \theta = 30^\circ \): - \( \cos 30^\circ = \frac{\sqrt{3}}{2} \) - \( \sin 30^\circ = \frac{1}{2} \) Thus, - \( F_{g\perp} = mg \cdot \frac{\sqrt{3}}{2} \) - \( F_{g\parallel} = mg \cdot \frac{1}{2} \) ### Step 3: Calculate the Normal Force The normal force \( N \) is equal to the perpendicular component of the weight: \[ N = mg \cos \theta = mg \cdot \frac{\sqrt{3}}{2} \] ### Step 4: Calculate the Frictional Force The frictional force \( F_f \) can be calculated using the coefficient of kinetic friction \( \mu \): \[ F_f = \mu N = \frac{1}{\sqrt{3}} \cdot \left( mg \cdot \frac{\sqrt{3}}{2} \right) = \frac{mg}{2} \] ### Step 5: Write the Equation of Motion The net force acting on the ice cube along the incline can be expressed as: \[ F_{\text{net}} = F_{g\parallel} - F_f \] Substituting the values: \[ F_{\text{net}} = mg \cdot \frac{1}{2} - \frac{mg}{2} = 0 \] ### Step 6: Apply Newton's Second Law According to Newton's second law: \[ F_{\text{net}} = ma \] Since \( F_{\text{net}} = 0 \): \[ 0 = ma \] This implies that: \[ a = 0 \] ### Conclusion The acceleration of the ice cube on the inclined plane is \( 0 \, \text{m/s}^2 \). This means the ice cube moves with constant velocity. ---

To find the acceleration of the ice cube on the inclined plane, we can follow these steps: ### Step 1: Identify the Forces Acting on the Ice Cube The forces acting on the ice cube are: 1. The gravitational force (weight) acting downwards: \( F_g = mg \) 2. The normal force \( N \) acting perpendicular to the inclined plane. 3. The frictional force \( F_f \) acting up the incline. ...
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