A block of mass m is kept on a horizontal ruler. The frilction coefficient between the ruler and the block is `mu`. The ruler is fixed at one block is at a distance L from the fixed end. The ruler is rotated about the fixed end. What can the maximum angular speed be for which the block does not slip?

Options

A. `sqrt((2 mu g)/(L))`
B. `sqrt((3 mu g)/(L))`
C. `sqrt((mu g)/(L))`
D. `sqrt((2L)/(mu g))`

Answer

C

Explanation

If `omega` is max. f is max
`:.mu N = n omega^(2) L`
`mu N g = m omega^(2) L omega = sqrt((mu g)/(L))`