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A particle just clears a wall of heig...

A particle just clears a wall of height b at distance a and strikes the ground at a distance c from the point of projection. The angle of projection is (1) `tan^(-1)b/(a c)` (2) `"45"^o` (3) `tan^(-1)(b c)/(a(c-a)` (4) `tan^(-1)(b c)/a`

A

In figure lift is moving along x-axis then value of T may be, zero

B

Lift moving toward right along x-axis with decreasing speed then value of N may be, `gt mg`

C

Lift is moving downward direction with constant velocity then value of T may be, `lt mg`

D

Lift is moving downward direction with constant velocity then value of T may be, = mg

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`T cos theta = mg implies T = m sqrt((g^(2) + a^(2)))`
`T sin theta = ma `
`implies T gt mg` if a is non-zero and
mg if a is zero
(B) `implies` N = ma can be greater less or equal to mg
(c ) `implies` T = mg + ma is greater, less or equal to mg according to as a is positive, negative of zero
(D) `implies ` T = mg
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